3.26.17 \(\int (d+e x)^2 (a+b x+c x^2)^{3/4} \, dx\) [2517]

3.26.17.1 Optimal result

Integrand size = 22, antiderivative size = 630 \[ \int (d+e x)^2 \left (a+b x+c x^2\right )^{3/4} \, dx=\frac {\left (36 c^2 d^2+11 b^2 e^2-4 c e (9 b d+2 a e)\right ) (b+2 c x) \left (a+b x+c x^2\right )^{3/4}}{180 c^3}+\frac {11 e (2 c d-b e) \left (a+b x+c x^2\right )^{7/4}}{63 c^2}+\frac {2 e (d+e x) \left (a+b x+c x^2\right )^{7/4}}{9 c}-\frac {\sqrt {b^2-4 a c} \left (36 c^2 d^2+11 b^2 e^2-4 c e (9 b d+2 a e)\right ) (b+2 c x) \sqrt [4]{a+b x+c x^2}}{120 c^{7/2} \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )}+\frac {\left (b^2-4 a c\right )^{7/4} \left (36 c^2 d^2+11 b^2 e^2-4 c e (9 b d+2 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )^2}} \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right ) E\left (2 \arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right )|\frac {1}{2}\right )}{120 \sqrt {2} c^{15/4} (b+2 c x)}-\frac {\left (b^2-4 a c\right )^{7/4} \left (36 c^2 d^2+11 b^2 e^2-4 c e (9 b d+2 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )^2}} \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right ),\frac {1}{2}\right )}{240 \sqrt {2} c^{15/4} (b+2 c x)} \]

output

1/180*(36*c^2*d^2+11*b^2*e^2-4*c*e*(2*a*e+9*b*d))*(2*c*x+b)*(c*x^2+b*x+a)^ 
(3/4)/c^3+11/63*e*(-b*e+2*c*d)*(c*x^2+b*x+a)^(7/4)/c^2+2/9*e*(e*x+d)*(c*x^ 
2+b*x+a)^(7/4)/c-1/120*(36*c^2*d^2+11*b^2*e^2-4*c*e*(2*a*e+9*b*d))*(2*c*x+ 
b)*(c*x^2+b*x+a)^(1/4)*(-4*a*c+b^2)^(1/2)/c^(7/2)/(1+2*c^(1/2)*(c*x^2+b*x+ 
a)^(1/2)/(-4*a*c+b^2)^(1/2))+1/240*(-4*a*c+b^2)^(7/4)*(36*c^2*d^2+11*b^2*e 
^2-4*c*e*(2*a*e+9*b*d))*(cos(2*arctan(c^(1/4)*(c*x^2+b*x+a)^(1/4)*2^(1/2)/ 
(-4*a*c+b^2)^(1/4)))^2)^(1/2)/cos(2*arctan(c^(1/4)*(c*x^2+b*x+a)^(1/4)*2^( 
1/2)/(-4*a*c+b^2)^(1/4)))*EllipticE(sin(2*arctan(c^(1/4)*(c*x^2+b*x+a)^(1/ 
4)*2^(1/2)/(-4*a*c+b^2)^(1/4))),1/2*2^(1/2))*(1+2*c^(1/2)*(c*x^2+b*x+a)^(1 
/2)/(-4*a*c+b^2)^(1/2))*((2*c*x+b)^2/(-4*a*c+b^2)/(1+2*c^(1/2)*(c*x^2+b*x+ 
a)^(1/2)/(-4*a*c+b^2)^(1/2))^2)^(1/2)/c^(15/4)/(2*c*x+b)*2^(1/2)-1/480*(-4 
*a*c+b^2)^(7/4)*(36*c^2*d^2+11*b^2*e^2-4*c*e*(2*a*e+9*b*d))*(cos(2*arctan( 
c^(1/4)*(c*x^2+b*x+a)^(1/4)*2^(1/2)/(-4*a*c+b^2)^(1/4)))^2)^(1/2)/cos(2*ar 
ctan(c^(1/4)*(c*x^2+b*x+a)^(1/4)*2^(1/2)/(-4*a*c+b^2)^(1/4)))*EllipticF(si 
n(2*arctan(c^(1/4)*(c*x^2+b*x+a)^(1/4)*2^(1/2)/(-4*a*c+b^2)^(1/4))),1/2*2^ 
(1/2))*(1+2*c^(1/2)*(c*x^2+b*x+a)^(1/2)/(-4*a*c+b^2)^(1/2))*((2*c*x+b)^2/( 
-4*a*c+b^2)/(1+2*c^(1/2)*(c*x^2+b*x+a)^(1/2)/(-4*a*c+b^2)^(1/2))^2)^(1/2)/ 
c^(15/4)/(2*c*x+b)*2^(1/2)
 

3.26.17.2 Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 10.23 (sec) , antiderivative size = 196, normalized size of antiderivative = 0.31 \[ \int (d+e x)^2 \left (a+b x+c x^2\right )^{3/4} \, dx=\frac {11 e (2 c d-b e) (a+x (b+c x))^{7/4}+14 c e (d+e x) (a+x (b+c x))^{7/4}-\frac {7 \left (-9 c^2 d^2-\frac {11 b^2 e^2}{4}+c e (9 b d+2 a e)\right ) (b+2 c x) \left (8 c (a+x (b+c x))-3 \sqrt {2} \left (b^2-4 a c\right ) \sqrt [4]{\frac {c (a+x (b+c x))}{-b^2+4 a c}} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {1}{2},\frac {3}{2},\frac {(b+2 c x)^2}{b^2-4 a c}\right )\right )}{40 c^2 \sqrt [4]{a+x (b+c x)}}}{63 c^2} \]

input

Integrate[(d + e*x)^2*(a + b*x + c*x^2)^(3/4),x]
 

output

(11*e*(2*c*d - b*e)*(a + x*(b + c*x))^(7/4) + 14*c*e*(d + e*x)*(a + x*(b + 
 c*x))^(7/4) - (7*(-9*c^2*d^2 - (11*b^2*e^2)/4 + c*e*(9*b*d + 2*a*e))*(b + 
 2*c*x)*(8*c*(a + x*(b + c*x)) - 3*Sqrt[2]*(b^2 - 4*a*c)*((c*(a + x*(b + c 
*x)))/(-b^2 + 4*a*c))^(1/4)*Hypergeometric2F1[1/4, 1/2, 3/2, (b + 2*c*x)^2 
/(b^2 - 4*a*c)]))/(40*c^2*(a + x*(b + c*x))^(1/4)))/(63*c^2)
 

3.26.17.3 Rubi [A] (verified)

Time = 0.61 (sec) , antiderivative size = 681, normalized size of antiderivative = 1.08, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.364, Rules used = {1166, 27, 1160, 1087, 1094, 834, 761, 1510}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int (d+e x)^2 \left (a+b x+c x^2\right )^{3/4} \, dx\)

\(\Big \downarrow \) 1166

\(\displaystyle \frac {2 \int \frac {1}{4} \left (18 c d^2-7 b e d-4 a e^2+11 e (2 c d-b e) x\right ) \left (c x^2+b x+a\right )^{3/4}dx}{9 c}+\frac {2 e (d+e x) \left (a+b x+c x^2\right )^{7/4}}{9 c}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int \left (18 c d^2-7 b e d-4 a e^2+11 e (2 c d-b e) x\right ) \left (c x^2+b x+a\right )^{3/4}dx}{18 c}+\frac {2 e (d+e x) \left (a+b x+c x^2\right )^{7/4}}{9 c}\)

\(\Big \downarrow \) 1160

\(\displaystyle \frac {\frac {\left (-4 c e (2 a e+9 b d)+11 b^2 e^2+36 c^2 d^2\right ) \int \left (c x^2+b x+a\right )^{3/4}dx}{2 c}+\frac {22 e \left (a+b x+c x^2\right )^{7/4} (2 c d-b e)}{7 c}}{18 c}+\frac {2 e (d+e x) \left (a+b x+c x^2\right )^{7/4}}{9 c}\)

\(\Big \downarrow \) 1087

\(\displaystyle \frac {\frac {\left (-4 c e (2 a e+9 b d)+11 b^2 e^2+36 c^2 d^2\right ) \left (\frac {(b+2 c x) \left (a+b x+c x^2\right )^{3/4}}{5 c}-\frac {3 \left (b^2-4 a c\right ) \int \frac {1}{\sqrt [4]{c x^2+b x+a}}dx}{20 c}\right )}{2 c}+\frac {22 e \left (a+b x+c x^2\right )^{7/4} (2 c d-b e)}{7 c}}{18 c}+\frac {2 e (d+e x) \left (a+b x+c x^2\right )^{7/4}}{9 c}\)

\(\Big \downarrow \) 1094

\(\displaystyle \frac {\frac {\left (-4 c e (2 a e+9 b d)+11 b^2 e^2+36 c^2 d^2\right ) \left (\frac {(b+2 c x) \left (a+b x+c x^2\right )^{3/4}}{5 c}-\frac {3 \left (b^2-4 a c\right ) \sqrt {(b+2 c x)^2} \int \frac {\sqrt {c x^2+b x+a}}{\sqrt {b^2-4 a c+4 c \left (c x^2+b x+a\right )}}d\sqrt [4]{c x^2+b x+a}}{5 c (b+2 c x)}\right )}{2 c}+\frac {22 e \left (a+b x+c x^2\right )^{7/4} (2 c d-b e)}{7 c}}{18 c}+\frac {2 e (d+e x) \left (a+b x+c x^2\right )^{7/4}}{9 c}\)

\(\Big \downarrow \) 834

\(\displaystyle \frac {\frac {\left (-4 c e (2 a e+9 b d)+11 b^2 e^2+36 c^2 d^2\right ) \left (\frac {(b+2 c x) \left (a+b x+c x^2\right )^{3/4}}{5 c}-\frac {3 \left (b^2-4 a c\right ) \sqrt {(b+2 c x)^2} \left (\frac {\sqrt {b^2-4 a c} \int \frac {1}{\sqrt {b^2-4 a c+4 c \left (c x^2+b x+a\right )}}d\sqrt [4]{c x^2+b x+a}}{2 \sqrt {c}}-\frac {\sqrt {b^2-4 a c} \int \frac {1-\frac {2 \sqrt {c} \sqrt {c x^2+b x+a}}{\sqrt {b^2-4 a c}}}{\sqrt {b^2-4 a c+4 c \left (c x^2+b x+a\right )}}d\sqrt [4]{c x^2+b x+a}}{2 \sqrt {c}}\right )}{5 c (b+2 c x)}\right )}{2 c}+\frac {22 e \left (a+b x+c x^2\right )^{7/4} (2 c d-b e)}{7 c}}{18 c}+\frac {2 e (d+e x) \left (a+b x+c x^2\right )^{7/4}}{9 c}\)

\(\Big \downarrow \) 761

\(\displaystyle \frac {\frac {\left (-4 c e (2 a e+9 b d)+11 b^2 e^2+36 c^2 d^2\right ) \left (\frac {(b+2 c x) \left (a+b x+c x^2\right )^{3/4}}{5 c}-\frac {3 \left (b^2-4 a c\right ) \sqrt {(b+2 c x)^2} \left (\frac {\left (b^2-4 a c\right )^{3/4} \left (\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}+1\right ) \sqrt {\frac {4 c \left (a+b x+c x^2\right )-4 a c+b^2}{\left (b^2-4 a c\right ) \left (\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}+1\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{c x^2+b x+a}}{\sqrt [4]{b^2-4 a c}}\right ),\frac {1}{2}\right )}{4 \sqrt {2} c^{3/4} \sqrt {4 c \left (a+b x+c x^2\right )-4 a c+b^2}}-\frac {\sqrt {b^2-4 a c} \int \frac {1-\frac {2 \sqrt {c} \sqrt {c x^2+b x+a}}{\sqrt {b^2-4 a c}}}{\sqrt {b^2-4 a c+4 c \left (c x^2+b x+a\right )}}d\sqrt [4]{c x^2+b x+a}}{2 \sqrt {c}}\right )}{5 c (b+2 c x)}\right )}{2 c}+\frac {22 e \left (a+b x+c x^2\right )^{7/4} (2 c d-b e)}{7 c}}{18 c}+\frac {2 e (d+e x) \left (a+b x+c x^2\right )^{7/4}}{9 c}\)

\(\Big \downarrow \) 1510

\(\displaystyle \frac {\frac {\left (-4 c e (2 a e+9 b d)+11 b^2 e^2+36 c^2 d^2\right ) \left (\frac {(b+2 c x) \left (a+b x+c x^2\right )^{3/4}}{5 c}-\frac {3 \left (b^2-4 a c\right ) \sqrt {(b+2 c x)^2} \left (\frac {\left (b^2-4 a c\right )^{3/4} \left (\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}+1\right ) \sqrt {\frac {4 c \left (a+b x+c x^2\right )-4 a c+b^2}{\left (b^2-4 a c\right ) \left (\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}+1\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{c x^2+b x+a}}{\sqrt [4]{b^2-4 a c}}\right ),\frac {1}{2}\right )}{4 \sqrt {2} c^{3/4} \sqrt {4 c \left (a+b x+c x^2\right )-4 a c+b^2}}-\frac {\sqrt {b^2-4 a c} \left (\frac {\sqrt [4]{b^2-4 a c} \left (\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}+1\right ) \sqrt {\frac {4 c \left (a+b x+c x^2\right )-4 a c+b^2}{\left (b^2-4 a c\right ) \left (\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}+1\right )^2}} E\left (2 \arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{c x^2+b x+a}}{\sqrt [4]{b^2-4 a c}}\right )|\frac {1}{2}\right )}{\sqrt {2} \sqrt [4]{c} \sqrt {4 c \left (a+b x+c x^2\right )-4 a c+b^2}}-\frac {\sqrt [4]{a+b x+c x^2} \sqrt {4 c \left (a+b x+c x^2\right )-4 a c+b^2}}{\left (b^2-4 a c\right ) \left (\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}+1\right )}\right )}{2 \sqrt {c}}\right )}{5 c (b+2 c x)}\right )}{2 c}+\frac {22 e \left (a+b x+c x^2\right )^{7/4} (2 c d-b e)}{7 c}}{18 c}+\frac {2 e (d+e x) \left (a+b x+c x^2\right )^{7/4}}{9 c}\)

input

Int[(d + e*x)^2*(a + b*x + c*x^2)^(3/4),x]
 

output

(2*e*(d + e*x)*(a + b*x + c*x^2)^(7/4))/(9*c) + ((22*e*(2*c*d - b*e)*(a + 
b*x + c*x^2)^(7/4))/(7*c) + ((36*c^2*d^2 + 11*b^2*e^2 - 4*c*e*(9*b*d + 2*a 
*e))*(((b + 2*c*x)*(a + b*x + c*x^2)^(3/4))/(5*c) - (3*(b^2 - 4*a*c)*Sqrt[ 
(b + 2*c*x)^2]*(-1/2*(Sqrt[b^2 - 4*a*c]*(-(((a + b*x + c*x^2)^(1/4)*Sqrt[b 
^2 - 4*a*c + 4*c*(a + b*x + c*x^2)])/((b^2 - 4*a*c)*(1 + (2*Sqrt[c]*Sqrt[a 
 + b*x + c*x^2])/Sqrt[b^2 - 4*a*c]))) + ((b^2 - 4*a*c)^(1/4)*(1 + (2*Sqrt[ 
c]*Sqrt[a + b*x + c*x^2])/Sqrt[b^2 - 4*a*c])*Sqrt[(b^2 - 4*a*c + 4*c*(a + 
b*x + c*x^2))/((b^2 - 4*a*c)*(1 + (2*Sqrt[c]*Sqrt[a + b*x + c*x^2])/Sqrt[b 
^2 - 4*a*c])^2)]*EllipticE[2*ArcTan[(Sqrt[2]*c^(1/4)*(a + b*x + c*x^2)^(1/ 
4))/(b^2 - 4*a*c)^(1/4)], 1/2])/(Sqrt[2]*c^(1/4)*Sqrt[b^2 - 4*a*c + 4*c*(a 
 + b*x + c*x^2)])))/Sqrt[c] + ((b^2 - 4*a*c)^(3/4)*(1 + (2*Sqrt[c]*Sqrt[a 
+ b*x + c*x^2])/Sqrt[b^2 - 4*a*c])*Sqrt[(b^2 - 4*a*c + 4*c*(a + b*x + c*x^ 
2))/((b^2 - 4*a*c)*(1 + (2*Sqrt[c]*Sqrt[a + b*x + c*x^2])/Sqrt[b^2 - 4*a*c 
])^2)]*EllipticF[2*ArcTan[(Sqrt[2]*c^(1/4)*(a + b*x + c*x^2)^(1/4))/(b^2 - 
 4*a*c)^(1/4)], 1/2])/(4*Sqrt[2]*c^(3/4)*Sqrt[b^2 - 4*a*c + 4*c*(a + b*x + 
 c*x^2)])))/(5*c*(b + 2*c*x))))/(2*c))/(18*c)
 

3.26.17.3.1 Defintions of rubi rules used

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 761

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b/a, 4]}, Simp[( 
1 + q^2*x^2)*(Sqrt[(a + b*x^4)/(a*(1 + q^2*x^2)^2)]/(2*q*Sqrt[a + b*x^4]))* 
EllipticF[2*ArcTan[q*x], 1/2], x]] /; FreeQ[{a, b}, x] && PosQ[b/a]
 

rule 834

Int[(x_)^2/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b/a, 2]}, S 
imp[1/q   Int[1/Sqrt[a + b*x^4], x], x] - Simp[1/q   Int[(1 - q*x^2)/Sqrt[a 
 + b*x^4], x], x]] /; FreeQ[{a, b}, x] && PosQ[b/a]
 

rule 1087

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(b + 2*c*x) 
*((a + b*x + c*x^2)^p/(2*c*(2*p + 1))), x] - Simp[p*((b^2 - 4*a*c)/(2*c*(2* 
p + 1)))   Int[(a + b*x + c*x^2)^(p - 1), x], x] /; FreeQ[{a, b, c}, x] && 
GtQ[p, 0] && (IntegerQ[4*p] || IntegerQ[3*p])
 

rule 1094

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[4*(Sqrt[(b 
+ 2*c*x)^2]/(b + 2*c*x))   Subst[Int[x^(4*(p + 1) - 1)/Sqrt[b^2 - 4*a*c + 4 
*c*x^4], x], x, (a + b*x + c*x^2)^(1/4)], x] /; FreeQ[{a, b, c}, x] && Inte 
gerQ[4*p]
 

rule 1160

Int[((d_.) + (e_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol 
] :> Simp[e*((a + b*x + c*x^2)^(p + 1)/(2*c*(p + 1))), x] + Simp[(2*c*d - b 
*e)/(2*c)   Int[(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, p}, x] 
 && NeQ[p, -1]
 

rule 1166

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_S 
ymbol] :> Simp[e*(d + e*x)^(m - 1)*((a + b*x + c*x^2)^(p + 1)/(c*(m + 2*p + 
 1))), x] + Simp[1/(c*(m + 2*p + 1))   Int[(d + e*x)^(m - 2)*Simp[c*d^2*(m 
+ 2*p + 1) - e*(a*e*(m - 1) + b*d*(p + 1)) + e*(2*c*d - b*e)*(m + p)*x, x]* 
(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, m, p}, x] && If[Ration 
alQ[m], GtQ[m, 1], SumSimplerQ[m, -2]] && NeQ[m + 2*p + 1, 0] && IntQuadrat 
icQ[a, b, c, d, e, m, p, x]
 

rule 1510

Int[((d_) + (e_.)*(x_)^2)/Sqrt[(a_) + (c_.)*(x_)^4], x_Symbol] :> With[{q = 
 Rt[c/a, 4]}, Simp[(-d)*x*(Sqrt[a + c*x^4]/(a*(1 + q^2*x^2))), x] + Simp[d* 
(1 + q^2*x^2)*(Sqrt[(a + c*x^4)/(a*(1 + q^2*x^2)^2)]/(q*Sqrt[a + c*x^4]))*E 
llipticE[2*ArcTan[q*x], 1/2], x] /; EqQ[e + d*q^2, 0]] /; FreeQ[{a, c, d, e 
}, x] && PosQ[c/a]
 

3.26.17.4 Maple [F]

\[\int \left (e x +d \right )^{2} \left (c \,x^{2}+b x +a \right )^{\frac {3}{4}}d x\]

input

int((e*x+d)^2*(c*x^2+b*x+a)^(3/4),x)
 

output

int((e*x+d)^2*(c*x^2+b*x+a)^(3/4),x)
 

3.26.17.5 Fricas [F]

\[ \int (d+e x)^2 \left (a+b x+c x^2\right )^{3/4} \, dx=\int { {\left (c x^{2} + b x + a\right )}^{\frac {3}{4}} {\left (e x + d\right )}^{2} \,d x } \]

input

integrate((e*x+d)^2*(c*x^2+b*x+a)^(3/4),x, algorithm="fricas")
 

output

integral((e^2*x^2 + 2*d*e*x + d^2)*(c*x^2 + b*x + a)^(3/4), x)
 

3.26.17.6 Sympy [F]

\[ \int (d+e x)^2 \left (a+b x+c x^2\right )^{3/4} \, dx=\int \left (d + e x\right )^{2} \left (a + b x + c x^{2}\right )^{\frac {3}{4}}\, dx \]

input

integrate((e*x+d)**2*(c*x**2+b*x+a)**(3/4),x)
 

output

Integral((d + e*x)**2*(a + b*x + c*x**2)**(3/4), x)
 

3.26.17.7 Maxima [F]

\[ \int (d+e x)^2 \left (a+b x+c x^2\right )^{3/4} \, dx=\int { {\left (c x^{2} + b x + a\right )}^{\frac {3}{4}} {\left (e x + d\right )}^{2} \,d x } \]

input

integrate((e*x+d)^2*(c*x^2+b*x+a)^(3/4),x, algorithm="maxima")
 

output

integrate((c*x^2 + b*x + a)^(3/4)*(e*x + d)^2, x)
 

3.26.17.8 Giac [F]

\[ \int (d+e x)^2 \left (a+b x+c x^2\right )^{3/4} \, dx=\int { {\left (c x^{2} + b x + a\right )}^{\frac {3}{4}} {\left (e x + d\right )}^{2} \,d x } \]

input

integrate((e*x+d)^2*(c*x^2+b*x+a)^(3/4),x, algorithm="giac")
 

output

integrate((c*x^2 + b*x + a)^(3/4)*(e*x + d)^2, x)
 

3.26.17.9 Mupad [F(-1)]

Timed out. \[ \int (d+e x)^2 \left (a+b x+c x^2\right )^{3/4} \, dx=\int {\left (d+e\,x\right )}^2\,{\left (c\,x^2+b\,x+a\right )}^{3/4} \,d x \]

input

int((d + e*x)^2*(a + b*x + c*x^2)^(3/4),x)
 

output

int((d + e*x)^2*(a + b*x + c*x^2)^(3/4), x)